Oracle connection string with at sign @ in pasword

Question

I have a code that connect to oracle using connection string:

conn = cx_Oracle.connect('username/password@server:port/services')

But the problem is my password contain @ character so it may become

conn = cx_Oracle.connect('username/p@ssword@server:port/services')

it return

DatabaseError: ORA-12154: TNS:could not resolve the connect identifier
specified

I use Django with Oracle with this settings

DATABASES = {
    'default': {
        'ENGINE': 'django.db.backends.oracle', 
        'NAME': 'Services',  
        'USER': 'user',                      
        'PASSWORD': 'p@ssword',                  
        'HOST': 'ip',                      
        'PORT': 'port',                      
    }
}

I cant change password 🙁 Does anyone know this problem?

Asked By: James

||

Source

Answer 1

I haven’t tried cx_Oracle, but you might be able to connect by specifying the individual parameters –

conn = cx_Oracle.connect(user='username', password='p@ssword', dsn='server:port/services')

OR

dsn_tns = cx_Oracle.makedsn('server', 'port', 'services')
conn = cx_Oracle.connect(user='username', password='p@ssword', dsn=dsn_tns)

Answered By: Shashank Agarwal

Answer 2

Does this work?

conn = cx_Oracle.connect('username/"p@ssword"@server:port/services')

Answered By: Wernfried Domscheit

Answer 3

You can use any of the following way based on Service Name or SID whatever you have.

With SID:

dsn_tns = cx_Oracle.makedsn('server', 'port', 'sid')
conn = cx_Oracle.connect(user='username', password='p@ssword', dsn=dsn_tns)

OR

With Service Name:

dsn_tns = cx_Oracle.makedsn('server', 'port', service_name='service_name')
conn = cx_Oracle.connect(user='username', password='p@ssword', dsn=dsn_tns)

Answered By: Sahil Chhabra

Answer 4

FYI: This was a long-standing bug in Django. The first stable version containing the fix is v2.1

Answered By: Shane

Answer 5

All the answers mentioned here did not work for SQLAlchemy.

Parsing the characters to create a valid URL worked:

from sqlalchemy.engine import create_engine
import urllib.parse

url_password = urllib.parse.quote_plus(password)
connection_string = f"oracle+cx_oracle://{username}:{url_password}@{server}:{port}/?service_name={service}"
connection = create_engine(connection_string)

Should probably do the same with the other components of the connection string.

Answered By: Chris du Plessis

Oracle connection string with at sign @ in pasword

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