Python – round up to the nearest ten
Question:
If I get the number 46 and I want to round up to the nearest ten. How do can I do this in python?
46 goes to 50.
Answers:
Here is one way to do it:
>>> n = 46
>>> (n + 9) // 10 * 10
50
round does take negative ndigits parameter!
>>> round(46,-1)
50
may solve your case.
You can use math.ceil() to round up, and then multiply by 10
import math
def roundup(x):
return int(math.ceil(x / 10.0)) * 10
To use just do
>>roundup(45)
50
This will round down correctly as well:
>>> n = 46
>>> rem = n % 10
>>> if rem < 5:
... n = int(n / 10) * 10
... else:
... n = int((n + 10) / 10) * 10
...
>>> 50
If I get the number 46 and I want to round up to the nearest ten. How do can I do this in python?
46 goes to 50.
Here is one way to do it:
>>> n = 46
>>> (n + 9) // 10 * 10
50
round does take negative ndigits parameter!
>>> round(46,-1)
50
may solve your case.
You can use math.ceil() to round up, and then multiply by 10
import math
def roundup(x):
return int(math.ceil(x / 10.0)) * 10
To use just do
>>roundup(45)
50
This will round down correctly as well:
>>> n = 46
>>> rem = n % 10
>>> if rem < 5:
... n = int(n / 10) * 10
... else:
... n = int((n + 10) / 10) * 10
...
>>> 50