How to change the message in a Python AssertionError?

Question

I’m writing per the following, in which I try to produce a decent error message when comparing two multiline blocks of Unicode text. The interior method that does the comparison raises an assertion, but the default explanation is useless to me

I need to add something to code such as this below:

def assert_long_strings_equal(one, other):
    lines_one = one.splitlines()
    lines_other = other.splitlines()
    for line1, line2 in zip(lines_one, lines_other):
        try:
            my_assert_equal(line1, line2)
        except AssertionError, error:
            # Add some information to the printed result of error??!
            raise

I cannot figure out how to change the printed error message in the assertionerror I catch. I always get AssertionError: u'something' != 'something else', which only shows the first line of the output.

How can I change the assertion message to print out whatever I want?

If it’s relevant, I am using nose to run the test.

Asked By: Andres Jaan Tack

||

Source

Answer 1

You can pass the desired message when creating the exception.

raise AssertionError(line1 + ' != ' + line2)

Hope this helps.

Answered By: zchtodd

Answer 2

assert expression, info

For instance,

>>> assert False, "Oopsie"
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AssertionError: Oopsie

From the docs:

Assert statements are a convenient way
to insert debugging assertions into a
program:
assert_stmt ::=  "assert" expression
["," expression] 
The simple form,
assert expression, is equivalent to
if __debug__:
    if not expression:
        raise AssertionError 
The extended form
assert expression1, expression2
is equivalent to
if __debug__:
    if not expression1:
        raise AssertionError(expression2)
These equivalences assume that
__debug__ and AssertionError refer to the built-in variables with those
names. In the current implementation,
the built-in variable __debug__ is
True under normal circumstances, False
when optimization is requested
(command line option -O). The current
code generator emits no code for an
assert statement when optimization is
requested at compile time. Note that
it is unnecessary to include the
source code for the expression that
failed in the error message; it will
be displayed as part of the stack
trace.

Answered By: Katriel

Answer 3

You want to take the caught exception, convert it to a string, combine it with some additional string info, and raise a new exception.

x = 3
y = 5
try:
    assert( x == y )
except AssertionError, e:
    raise( AssertionError( "Additional info. %s"%e ) )

Answered By: Russell Borogove

Answer 4

Use e.args, e.message is deprecated.

try:
    assert False, "Hello!"
except AssertionError as e:
    e.args += ('some other', 'important', 'information', 42)
    raise

This preserves the original traceback. Its last part then looks like this:

AssertionError: ('Hello!', 'some other', 'important', 'information', 42)

Works in both Python 2.7 and Python 3.

Answered By: Honza Javorek

How to change the message in a Python AssertionError?

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