How can I make a dictionary / collections.counter that takesz into account the index in Python?

Question

I am aware of dictionaries and collection.Counters in Python.
My question is how can I make one that takes index of the string into account?
For example for this string: aaabaaa
I would like to make a tuples that contain each string in progression, keeping track of the count going left to right and resetting the count once a new alphanumeric is found.
For example, I like to see this output:
[(‘a’, 3), (‘b’, 1), (‘a’, 3)]

Any idea how to use the dictionary / Counter/ or is there some other data structure built into Python I can use?

Regards

Asked By: fynx

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Source

Answer 1

You could use groupby:

from itertools import groupby

m = [(k, sum(1 for _ in v)) for k, v in groupby('aaabaaa')]

print(m)

Output

[('a', 3), ('b', 1), ('a', 3)]

Explanation

The groupby function makes an iterator that returns consecutive keys and groups from the iterable, in this case 'aaabaaa'. The key k is the value identifying of the group, ['a', 'b', 'a']. The sum(1 for _ in v) count the amount of elements in the group.

Answered By: Dani Mesejo

How can I make a dictionary / collections.counter that takesz into account the index in Python?

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