How to print a linebreak in a python function?

The newline character is actually 'n'.

>>> A = ['a1', 'a2', 'a3']
>>> B = ['b1', 'b2', 'b3']

>>> for x in A:
        for i in B:
            print ">" + x + "n" + i

Outputs:

>a1
b1
>a1
b2
>a1
b3
>a2
b1
>a2
b2
>a2
b3
>a3
b1
>a3
b2
>a3
b3

Notice that you are using /n which is not correct!

for pair in zip(A, B):
    print ">"+'n'.join(pair)

n is an escape sequence, denoted by the backslash. A normal forward slash, such as /n will not do the job. In your code you are using /n instead of n.

All three way you can use for newline character :

'n'

"n"

"""n"""

You can print a native linebreak using the standard os library

import os
with open('test.txt','w') as f:
    f.write(os.linesep)

Also if you’re making it a console program, you can do: print(" ") and continue your program. I’ve found it the easiest way to separate my text.

A = ['a1', 'a2', 'a3'] 
B = ['b1', 'b2', 'b3']
for a,b in zip(A,B): 
    print(f">{a}n{b}")

Below python 3.6 instead of print(f">{a}n{b}") use print(">%sn%s" % (a, b))