Function in python that outputs either -1 or 0 or 1

Question

Is there like a (modified) round function where the output would be either -1,0,1 depending on to what number is the input the closest? E.g. 0 => 0, -2154 => -1, 10 => 1

Currently I am using normal if else statements:

if i == 0:
    return 0
elif i > 0: 
    return 1
else:
    return -1

But is there any way how I can make this a one-line code? By for instance using some modified round function.

Asked By: Sam333

||

Source

Answer 1

You can use numpy.sign()

import numpy as np

print(np.sign(1.2))
print(np.sign(-3.4))
print(np.sign(0))

output:

1.0
-1.0
0

Without any imports:

def sign(i):
    return (i>0) - (i<0)
    
print(sign(1))
print(sign(-3))
print(sign(0))

output:

1
-1
0

Answered By: joostblack

Answer 2

As the other answer commented, you can do it easily by using the numpy.sign() method, that directly returns your desired result.

However, you can do it directly using the built-in math function and the method copysign(x, y), which copies the sign of the second value to the first. By setting the first value as a boolean it will be interpreted as 0 if the original value is 0, and 1 otherwise. Then we copy the sign of value, which will transform the 1 into -1 or leave it positive.

from math import copysign

values = [1, 200, 0, -3, 45, -15]

for value in values:
    print(int(copysign(bool(value), value)))

which outputs:

Answered By: josepdecid

Answer 3

Here is a one-liner function using plain vanilla python and no imports. It can hardly get simpler than this.

def f(i):
    return -1 if i < 0 else int(bool(i))


In [5]: f(0)
Out[5]: 0

In [6]: f(1)
Out[6]: 1

In [7]: f(-5)
Out[7]: -1

Answered By: alec_djinn

Function in python that outputs either -1 or 0 or 1

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