How to check if a string is in a csv header

Question

I have this function:

def check_csv(final_word):
    with open("directory\trap_words.csv", "r") as f:
        reader = csv.reader(f)
        for i in reader:
            str(i)

            if final_word in i:
                return True
            else:
                return False

To check if the parameter final_word is in a csv file
But it does not return true even if the string is the same as one of the words in the csv file
This is the csv file:

Asked By: Rrezon Beqiri

||

Source

Answer 1

Your function loops through each line in the CSV file. On the first iteration (the first line) it checks if final_word in i: and then either returns back to the function caller true or false and then exits

I think the miss here is understanding that a return is the end of the logic, even inside a loop. Once a function returns, it stops processing.

So your code never gets past the first line of the csv. A fix is to get rid of the else and unindent return False to be outside of the loop and rerun

def check_csv(final_word):
    with open("directory\trap_words.csv", "r") as f:
        reader = csv.reader(f)
        for i in reader:
            str(i)

            if final_word in i:
                return True
        #only return false if we didn't already return true    
        return False

Answered By: JNevill

How to check if a string is in a csv header

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