How to delete a first and second line in each cell of column in csv
Question:
I didnt find solution for it, so maybe someone can help me
I have an csv file and it has "splitted_text" column, how can I delete the first and second line of text in each row?
enter image description here
Answers:
Based on the screenshot, I’m assuming that by:
delete the first and second line of text
you mean "delete the first and second element of each list contained in the splitter_text column"
In which case, you can simply apply a function along the column:
df["clean_splitted_text"] = df["splitted_text"].apply(lambda x: x[2:])
to save the cleaned output in a new column, or
df["splitted_text"] = df["splitted_text"].apply(lambda x: x[2:])
if you want to overwrite the content of that column (!)
Here, lambda x: x[2:] is a function that removes the first two elements of a list. If that list has 2 or fewer elements, then it returns the empty list: [].
I didnt find solution for it, so maybe someone can help me
I have an csv file and it has "splitted_text" column, how can I delete the first and second line of text in each row?
enter image description here
Based on the screenshot, I’m assuming that by:
delete the first and second line of text
you mean "delete the first and second element of each list contained in the splitter_text column"
In which case, you can simply apply a function along the column:
df["clean_splitted_text"] = df["splitted_text"].apply(lambda x: x[2:])
to save the cleaned output in a new column, or
df["splitted_text"] = df["splitted_text"].apply(lambda x: x[2:])
if you want to overwrite the content of that column (!)
Here, lambda x: x[2:] is a function that removes the first two elements of a list. If that list has 2 or fewer elements, then it returns the empty list: [].