Python updating list from constructor by object.attribute

Question

If a class is created with the attributes: name and list and the name attribute has a default value and the list is appending the name. Is it possible in somehow when I create an object "a" and type
"a.name = ‘x’ " that this ‘x’ will appear in the list given that the list is appending in the constructor?

class Person:
    list = []
    def __init__(self, name="Zed"):
        self.name = name
        self.list.append(name)

    def printList(self):
        print(self.list)


a = Person()
a.name = "Yasuo"
a.printList() #outputs Zed but Yasuo is expected.

Asked By: TheRi

||

Source

Answer 1

You can make name a property, and implement a setter that updates the list.

class Person:
    list = []
    def __init__(self, name="Zed"):
        self._name = name
        self.list.append(name)
    @property
    def name(self):
        return self._name
    @name.setter
    def name(self, name):
        if self._name in self.list:
            # remove the old name
            index = self.list.index(self.name)
            self.list[index] = name
        else:
            self.list.append(name)
        self._name = name
    def printList(self):
        print(self.list)

a = Person()
a.name = "Yasuo"
a.printList() # prints ['Yasuo']

Answered By: Barmar

Python updating list from constructor by object.attribute

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