How to convert the string to date time format?

Question

I have the following string 20211208_104755, representing date_time format. I want to convert it to the python datetime format using datetime.strip() method.

mydatetime = "20211208_104755"
datetime_object = datetime.strptime(mydatetime, '%y/%m/%d')

However I am getting the following error.

ValueError: time data '20211208' does not match format '%y/%m/%d'

Asked By: Lakpa Tamang

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Source

Answer 1

The second argument in strptime has to match the pattern of your datetime string. You can find the patterns and their meaning on https://docs.python.org/3/library/datetime.html

In your case, you can format it as

from datetime import datetime

mydatetime = "20211208_104755"
datetime_object = datetime.strptime(mydatetime, '%Y%m%d_%H%M%S')

print(datetime_object)


>>> 2021-12-08 10:47:55

Answered By: Gilian

Answer 2

what should work is to define how the mydatetime string is composed.
example:
%Y is the year (4 digits); check here for format (section strftime() Date Format Codes)

So in your example I would assume it’s like this:

mydatetime = "20211208_104755"
datetime_object = datetime.strptime(mydatetime, '%Y%m%d_%H%M%S')
print (datetime_object)

result

2021-12-08 10:47:55

and

type(datetime_object)
datetime.datetime

Answered By: adhg

How to convert the string to date time format?

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