How do I make a dictionary that doesn't return brackets

Question

I’m trying to make a dictionary that uses the call function ‘findPokemonInfo(name)’ and iterates through my csv file and returns information in this format:

attack: 49

capture_rate: 45

name: Bulbasaur

speed: 45

type: grass

The csv file is displayed like this: name,type,attack,speed,capture_rate

This is what I currently have:

def findPokemonInfo(name): 
    import csv 
    myFile = open('pokemon.csv',"r")
    csvReader = csv.reader(myFile,delimiter=",")
    next(csvReader)
    pokeMon = {}
    for row in csvReader:
        if (row[0] == name):
            pokeMon[row[0]] = {'attack':row[2], 'capture_rate':row[4], 'name':row[0], 'speed':row[3], 'type':row[1]}
            print (pokeMon)

Which returns:

findPokemonInfo(‘Bulbasaur’)

{'Bulbasaur': {'attack': '49', 'capture_rate': '45', 'name': 'Bulbasaur', 'speed': '45', 'type': 'grass'}}

Asked By: Jacob

||

Source

Answer 1

Print your dictionary this way:

d = {'Bulbasaur': {'attack': '49', 'capture_rate': '45', 'name': 'Bulbasaur', 'speed': '45', 'type': 'grass'}}

for key in d:
    for sub_key in d[key]:
        print(sub_key,": ", d[key][sub_key])

The output will be this:

attack :  49
capture_rate :  45
name :  Bulbasaur
speed :  45
type :  grass

Answered By: ARRAFI

How do I make a dictionary that doesn't return brackets

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