How to print a list with no leading commas with sep=", " into a string?

Question

The title maybe a bit confusing so here is the gist of it:

I have this list:

mylist = [0, 4, 8, 12]

and I want to print only the elements after some string.

So I did this:

print("The arithmetic sequence is:", *mylist, sep=", ")

The outcome that I want is

The arithmetic sequence is: 0, 4, 8, 12

However what I got is this:

The arithmetic sequence is:, 0, 4, 8, 12

Notice the extra comma in between the 0 and the colon

I’m guessing that sep=", " is the culprit, but I don’t know how to get rid of the leading comma

Asked By: Blueyu

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Source

Answer 1

The problem with sep= is that the string is inserted between all parameters, including between "The arithmetic sequence is:" and the first value in myList. Use a f-string and str.join instead. You’ll have to convert the values to strings as you go

>>> mylist = [0, 4, 8, 12]
>>> print(f"The arithmetic sequence is: {', '.join(str(v) for v in mylist)}")
The arithmetic sequence is: 0, 4, 8, 12

Answered By: tdelaney

Answer 2

mylist = [0, 4, 8, 12]
print("The arithmetic sequence is:", ', '.join(str(i) for i in mylist))

Answered By: Jethy11

How to print a list with no leading commas with sep=", " into a string?

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