Python sort a string in CSV

Question

I want to sort the every row of the CSV string with the following code

import csv

def sort_csv_columns(csv_string: str) -> str:
    # Split the CSV string into lines
    lines = csv_string.strip().split("n")

    # Split the first line (column names) and sort it case-insensitively
    header = lines[0].split(",")
    header.sort(key=str.lower)

    # Split the remaining lines (data rows) and sort them by the sorted header
    data = [line.split(",") for line in lines[1:]]
    data.sort(key=lambda row: [row[header.index(col)] for col in header])

    # Join the sorted data and header into a single CSV string
    sorted_csv = "n".join([",".join(header)] + [",".join(row) for row in data])
    return sorted_csv

# Test the function
csv_string = "Beth,Charles,Danielle,Adam,Ericn17945,10091,10088,3907,10132n2,12,13,48,11"
sorted_csv = sort_csv_columns(csv_string)
print(sorted_csv)

Output

Adam,Beth,Charles,Danielle,Eric
17945,10091,10088,3907,10132
2,12,13,48,11

Expected Output

Adam,Beth,Charles,Danielle,Ericn
3907,17945,10091,10088,10132n
48,2,12,13,11

What am I doing wrong

I am not able to sort the row besides the top header

Asked By: Rohit Sthapit

||

Source

Answer 1

As data represents your lines, then data.sort can only sort the lines between, them, not the lines content (the cells), you need to sort on each element of data
Also doing the following will always give 0,1,2,3,4 as you check index on the list on iterate on
```
[header.index(col) for col in header]
```

Sort header then reorder

You need sorting, but without sort method, you just need to reorder the values regarding the new header order

def sort_csv_columns(csv_string: str) -> str:
    lines = csv_string.strip().split("n")

    initial_header = lines[0].split(",")
    header = sorted(initial_header, key=str.lower)

    data = [line.split(",") for line in lines[1:]]
    data = [[row[initial_header.index(col)] for col in header]
            for row in data]

    sorted_csv = "n".join([",".join(header)] + [",".join(row) for row in data])
    return sorted_csv

Sort by header but maintain row together

You can avoid the reorder part if you sort the data while having a the content stored by column instead of rows

def sort_csv_columns(csv_string: str) -> str:
    data = [line.split(",") for line in csv_string.strip().split("n")]
    # [['Beth', 'Charles', 'Danielle', 'Adam', 'Eric'], ['17945', '10091', '10088', '3907', '10132']
    # , ['2', '12', '13', '48', '11']]
    data = list(zip(*data))
    # [('Beth', '17945', '2'), ('Charles', '10091', '12'), ('Danielle', '10088', '13'),
    #  ('Adam', '3907', '48'), ('Eric', '10132', '11')]
    
    # sort by first value : name
    data.sort(key=lambda row: row[0].lower())
    sorted_csv = "n".join([",".join(row) for row in zip(*data)])
    return sorted_csv

Answered By: azro

Python sort a string in CSV

Question:

Answers:

Sort header then reorder

Sort by header but maintain row together