How can we raise a HTTPError exception?

Question

I want to raise an exception whenever i get data value as None. How can we achieve it without using custom exception?

Ex:

def foo():
      <some code>
      return data

@store.route("/store", methods=["GET"])
def fun():
    try:
       data = foo()
       if not data:
           raise HTTPError()
    except HTTPError as he:
       return "Internal server error", 500

I tried above one, but its not working, appreciate your help

Asked By: DmUser

||

Source

Answer 1

In Python, you can raise an HTTPError exception using the raise keyword and passing an instance of the HTTPError class. The HTTPError class is part of the urllib.error module, which is a submodule of the urllib module.

Here is an example of how you can raise an HTTPError exception:

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from urllib.error import HTTPError

try:
# Code that may raise an HTTPError
raise HTTPError("HTTP Error occurred")

except HTTPError as e:
print("An HTTPError occurred:", e)
In this example, we’re importing the HTTPError class from the urllib.error module and then raising an instance of the HTTPError class inside a try-except block.

You can also raise an HTTPError by passing a status code and a message as arguments to the HTTPError class:

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raise HTTPError(404, "Not Found")
This will raise an exception with a status code of 404 and a message of "Not Found".

Please keep in mind that raising an exception should be used as a last resort and only when it is not possible to handle the error in any other way, such as by returning an error status code or message.

Answered By: Ram Sharma

Answer 2

I think sou can rais a http error as following:

from urllib2 import urlopen, HTTPError # or from urllib.error import HTTPError

def fooo():
   raise HTTPError()

fooo()

reference

Answered By: kaliiiiiiiii

How can we raise a HTTPError exception?

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