Running multiple scripts in sequence in Python

Question

I am running multiple scripts in sequence according to the list I and the following executable. However, when one of the script in folder (say, 2) runs into an error, it terminates instead of moving to folder 3. Basically I want the executable to move onto the next script if there is an error in the present script. How do I do this?

I=[1,2,3]
for i in I: 
    exec(open(rf"C:5100 nodes{i}5100_beta_0.01_50.0_1.0ND_3.py").read())

The error encountered while running script in folder 2 is

File "<string>", line 618, in <module>

ValueError: max() arg is an empty sequence

Asked By: rajunarlikar123

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Source

Answer 1

You could use a try-except block.

I=[1,2,3]
for i in I:
    try: 
        exec(open(rf"C:5100 nodes{i}5100_beta_0.01_50.0_1.0ND_3.py").read())
    except Error as e:
        print(e)

Answered By: Abhishek Sharma

Running multiple scripts in sequence in Python

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