best way to preserve numpy arrays on disk

Question:

I am looking for a fast way to preserve large numpy arrays. I want to save them to the disk in a binary format, then read them back into memory relatively fastly. cPickle is not fast enough, unfortunately.

I found numpy.savez and numpy.load. But the weird thing is, numpy.load loads a npy file into “memory-map”. That means regular manipulating of arrays really slow. For example, something like this would be really slow:

#!/usr/bin/python
import numpy as np;
import time; 
from tempfile import TemporaryFile

n = 10000000;

a = np.arange(n)
b = np.arange(n) * 10
c = np.arange(n) * -0.5

file = TemporaryFile()
np.savez(file,a = a, b = b, c = c);

file.seek(0)
t = time.time()
z = np.load(file)
print "loading time = ", time.time() - t

t = time.time()
aa = z['a']
bb = z['b']
cc = z['c']
print "assigning time = ", time.time() - t;

more precisely, the first line will be really fast, but the remaining lines that assign the arrays to obj are ridiculously slow:

loading time =  0.000220775604248
assining time =  2.72940087318

Is there any better way of preserving numpy arrays? Ideally, I want to be able to store multiple arrays in one file.

Asked By: CuriousMind

||

Answers:

I’m a big fan of hdf5 for storing large numpy arrays. There are two options for dealing with hdf5 in python:

http://www.pytables.org/

http://www.h5py.org/

Both are designed to work with numpy arrays efficiently.

Answered By: JoshAdel

savez() save data in a zip file, It may take some time to zip & unzip the file. You can use save() & load() function:

f = file("tmp.bin","wb")
np.save(f,a)
np.save(f,b)
np.save(f,c)
f.close()

f = file("tmp.bin","rb")
aa = np.load(f)
bb = np.load(f)
cc = np.load(f)
f.close()

To save multiple arrays in one file, you just need to open the file first, and then save or load the arrays in sequence.

Answered By: HYRY

There is now a HDF5 based clone of pickle called hickle!

https://github.com/telegraphic/hickle

import hickle as hkl 

data = {'name': 'test', 'data_arr': [1, 2, 3, 4]}

# Dump data to file
hkl.dump(data, 'new_data_file.hkl')

# Load data from file
data2 = hkl.load('new_data_file.hkl')

print(data == data2)

EDIT:

There also is the possibility to "pickle" directly into a compressed archive by doing:

import pickle, gzip, lzma, bz2

pickle.dump(data, gzip.open('data.pkl.gz', 'wb'))
pickle.dump(data, lzma.open('data.pkl.lzma', 'wb'))
pickle.dump(data, bz2.open('data.pkl.bz2', 'wb'))

compression


Appendix

import numpy as np
import matplotlib.pyplot as plt
import pickle, os, time
import gzip, lzma, bz2, h5py

compressions = ['pickle', 'h5py', 'gzip', 'lzma', 'bz2']
modules = dict(
    pickle=pickle, h5py=h5py, gzip=gzip, lzma=lzma, bz2=bz2
)

labels = ['pickle', 'h5py', 'pickle+gzip', 'pickle+lzma', 'pickle+bz2']
size = 1000

data = {}

# Random data
data['random'] = np.random.random((size, size))

# Not that random data
data['semi-random'] = np.zeros((size, size))
for i in range(size):
    for j in range(size):
        data['semi-random'][i, j] = np.sum(
            data['random'][i, :]) + np.sum(data['random'][:, j]
        )

# Not random data
data['not-random'] = np.arange(
    size * size, dtype=np.float64
).reshape((size, size))

sizes = {}

for key in data:

    sizes[key] = {}

    for compression in compressions:
        path = 'data.pkl.{}'.format(compression)

        if compression == 'pickle':
            time_start = time.time()
            pickle.dump(data[key], open(path, 'wb'))
            time_tot = time.time() - time_start
            sizes[key]['pickle'] = (
                os.path.getsize(path) * 10**-6, 
                time_tot.
            )
            os.remove(path)

        elif compression == 'h5py':
            time_start = time.time()
            with h5py.File(path, 'w') as h5f:
                h5f.create_dataset('data', data=data[key])
            time_tot = time.time() - time_start
            sizes[key][compression] = (os.path.getsize(path) * 10**-6, time_tot)
            os.remove(path)

        else:
            time_start = time.time()
            with modules[compression].open(path, 'wb') as fout:
                pickle.dump(data[key], fout)
            time_tot = time.time() - time_start
            sizes[key][labels[compressions.index(compression)]] = (
                os.path.getsize(path) * 10**-6, 
                time_tot,
            )
            os.remove(path)


f, ax_size = plt.subplots()
ax_time = ax_size.twinx()

x_ticks = labels
x = np.arange(len(x_ticks))

y_size = {}
y_time = {}
for key in data:
    y_size[key] = [sizes[key][x_ticks[i]][0] for i in x]
    y_time[key] = [sizes[key][x_ticks[i]][1] for i in x]

width = .2
viridis = plt.cm.viridis

p1 = ax_size.bar(x - width, y_size['random'], width, color = viridis(0))
p2 = ax_size.bar(x, y_size['semi-random'], width, color = viridis(.45))
p3 = ax_size.bar(x + width, y_size['not-random'], width, color = viridis(.9))
p4 = ax_time.bar(x - width, y_time['random'], .02, color='red')

ax_time.bar(x, y_time['semi-random'], .02, color='red')
ax_time.bar(x + width, y_time['not-random'], .02, color='red')

ax_size.legend(
    (p1, p2, p3, p4), 
    ('random', 'semi-random', 'not-random', 'saving time'),
    loc='upper center', 
    bbox_to_anchor=(.5, -.1), 
    ncol=4,
)
ax_size.set_xticks(x)
ax_size.set_xticklabels(x_ticks)

f.suptitle('Pickle Compression Comparison')
ax_size.set_ylabel('Size [MB]')
ax_time.set_ylabel('Time [s]')

f.savefig('sizes.pdf', bbox_inches='tight')
Answered By: Suuuehgi

Another possibility to store numpy arrays efficiently is Bloscpack:

#!/usr/bin/python
import numpy as np
import bloscpack as bp
import time

n = 10000000

a = np.arange(n)
b = np.arange(n) * 10
c = np.arange(n) * -0.5
tsizeMB = sum(i.size*i.itemsize for i in (a,b,c)) / 2**20.

blosc_args = bp.DEFAULT_BLOSC_ARGS
blosc_args['clevel'] = 6
t = time.time()
bp.pack_ndarray_file(a, 'a.blp', blosc_args=blosc_args)
bp.pack_ndarray_file(b, 'b.blp', blosc_args=blosc_args)
bp.pack_ndarray_file(c, 'c.blp', blosc_args=blosc_args)
t1 = time.time() - t
print "store time = %.2f (%.2f MB/s)" % (t1, tsizeMB / t1)

t = time.time()
a1 = bp.unpack_ndarray_file('a.blp')
b1 = bp.unpack_ndarray_file('b.blp')
c1 = bp.unpack_ndarray_file('c.blp')
t1 = time.time() - t
print "loading time = %.2f (%.2f MB/s)" % (t1, tsizeMB / t1)

and the output for my laptop (a relatively old MacBook Air with a Core2 processor):

$ python store-blpk.py
store time = 0.19 (1216.45 MB/s)
loading time = 0.25 (898.08 MB/s)

that means that it can store really fast, i.e. the bottleneck is typically the disk. However, as the compression ratios are pretty good here, the effective speed is multiplied by the compression ratios. Here are the sizes for these 76 MB arrays:

$ ll -h *.blp
-rw-r--r--  1 faltet  staff   921K Mar  6 13:50 a.blp
-rw-r--r--  1 faltet  staff   2.2M Mar  6 13:50 b.blp
-rw-r--r--  1 faltet  staff   1.4M Mar  6 13:50 c.blp

Please note that the use of the Blosc compressor is fundamental for achieving this. The same script but using ‘clevel’ = 0 (i.e. disabling compression):

$ python bench/store-blpk.py
store time = 3.36 (68.04 MB/s)
loading time = 2.61 (87.80 MB/s)

is clearly bottlenecked by the disk performance.

Answered By: Francesc

The lookup time is slow because when you use mmap to does not load content of array to memory when you invoke load method. Data is lazy loaded when particular data is needed.
And this happens in lookup in your case. But second lookup won`t be so slow.

This is nice feature of mmap when you have a big array you do not have to load whole data into memory.

To solve your can use joblib you can dump any object you want using joblib.dump even two or more numpy arrays, see the example

firstArray = np.arange(100)
secondArray = np.arange(50)
# I will put two arrays in dictionary and save to one file
my_dict = {'first' : firstArray, 'second' : secondArray}
joblib.dump(my_dict, 'file_name.dat')
Answered By: Michal

I’ve compared performance (space and time) for a number of ways to store numpy arrays. Few of them support multiple arrays per file, but perhaps it’s useful anyway.

benchmark for numpy array storage

Npy and binary files are both really fast and small for dense data. If the data is sparse or very structured, you might want to use npz with compression, which’ll save a lot of space but cost some load time.

If portability is an issue, binary is better than npy. If human readability is important, then you’ll have to sacrifice a lot of performance, but it can be achieved fairly well using csv (which is also very portable of course).

More details and the code are available at the github repo.

Answered By: Mark

‘Best’ depends on what your goal is. As others have said, a binary is maximally portable, but the problem is that you need to know about how the data is stored.

Darr saves your numpy array in a self-documented way based on flat binary and text files. This maximizes wide readability. It also automatically includes code on how to read your array in a variety of data science languages, such as numpy itself, but also R, Matlab, Julia etc.

Disclosure: I wrote the library.

Answered By: Gabriel