python-itertools

Aggregate row pair combinations and calculate difference using pandas Question: I am using the context and code of this question here: Aggregate all dataframe row pair combinations using pandas import pandas import itertools mygenes=[‘ABC1’, ‘ABC2’, ‘ABC3’, ‘ABC4’] df = pandas.DataFrame({‘Gene’ : [‘ABC1’, ‘ABC2’, ‘ABC3’, ‘ABC4′,’ABC5’], ‘case1’ : [0,1,1,0,0], ‘case2’ : [1,1,1,0,1], ‘control1’:[0,0,1,1,1], ‘control2’:[1,0,0,1,0] }) >>> …

How do I replace part of string with various combinations in lookup in Python? Question: I have the following code replacing every element with it’s short form in the lookup: case = ["MY_FIRST_RODEO"] lookup = {‘MY’: ‘M’, ‘FIRST’: ‘FRST’, ‘RODEO’ : ‘RD’, ‘FIRST_RODEO’: ‘FRD’, ‘MY_FIRST’: ‘MF’, ‘MY_FIRST_RODEO’: ‘MFR’} case_mod = [] for string in case: …

Python : Replace two for loops with the fastest way to sum the elements Question: I have list of 5 elements which could be 50000, now I want to sum all the combinations from the same list and create a dataframe from the results, so I am writing following code, x =list(range(1,5)) t=[] for i …

How do I add constraints to Itertools Product? Question: I am trying to list all products with numbers = [1,2,3,4,5,6,7,8] string length of 4 with some constraints. Position 0 must be < 8 Positions 2 and 3 must be < 6 With the current code it is printing every possible combination so I was wondering …

Why pandas deprecation of iteritems() is influencing the pd.DataFrame().columns? Question: I have a code that is using pandas everywhere. In various instances, wheather I am using Series or just calling .columns method, I receive this warning: C:Program FilesJetBrainsPyCharm Community Edition 2021.2.3pluginspython-cehelperspydev_pydevd_bundlepydevd_utils.py:609: FutureWarning: iteritems is deprecated and will be removed in a future version. Use .items …

fast deletion in a list with too many elements – PYTHON Question: How can I quickly delete elements in b from inside a ? import itertools a=list(itertools.product("12X",repeat=15)) b=list(itertools.product("1X",repeat=15)) print("a len = ",len(a)) print("b len = ",len(b)) for x in b: if x in a: a.remove(x) It’s very slow. Asked By: 333 || Source Answers: Convert …

Is there a more elegant way of getting permutations with replacement in python? Question: I currently want all permutations of a set of elements with replacement. Example: elements = [‘a’, ‘b’] permutations with replacement = [(‘a’, ‘a’, ‘a’), (‘a’, ‘a’, ‘b’), (‘a’, ‘b’, ‘a’), (‘a’, ‘b’, ‘b’), (‘b’, ‘a’, ‘a’), (‘b’, ‘a’, ‘b’), (‘b’, ‘b’, …

Improve itertools.pairwise() function Question: I am trying to create a custom function that improves the itertools pairwise function. Unlike the pairwise function, which returns pairs of items (n=2), I would like to be able to specify the grouping length (n=x). So that I can return groups of items of a specified length. Is this possible? …

Getting distinct values from from a list comprised of lists containing a comma delimited string Question: Main list: data = [ ["629-2, text1, 12"], ["629-2, text2, 12"], ["407-3, text9, 6"], ["407-3, text4, 6"], ["000-5, text7, 0"], ["000-5, text6, 0"], ] I want to get a list comprised of unique lists like so: data_unique = [ …

Grouping Python dictionaries in hierarchical form with multiple keys? Question: Here is my list of dicts: [{‘subtopic’: ‘kuku’, ‘topic’: ‘lulu’, ‘attachments’: [‘ttt’], ‘text’: ‘abc’}, {‘subtopic’: ‘tutu’, ‘topic’: ‘lulu’, ‘attachments’: [‘pipu’], ‘text’: ‘bubb’}, {‘subtopic’: ‘did’, ‘topic’: ‘lulu’, ‘attachments’: [‘ktop’], ‘text’: ‘gfg’}, {‘subtopic’: ‘polo’, ‘topic’: ‘lulu’, ‘attachments’: [‘vuvu’], ‘text’: ‘prolo’}, {‘subtopic’: ‘ssd’, ‘topic’: ‘lulu’, ‘attachments’: [‘jkjk’], ‘text’: …